IRFP240 IRFP9240 Mosfet 400W Amplifier Circuit

| August 8, 2019 Updated
IRFP240 IRFP9240 Mosfet 400W Amplifier Circuit

Despite the apparent simplicity, this amplifier showed excellent quality parameters, which allows you to safely rank it as a Hi-Fi equipment. The amplifier has a very pleasant sound in the mid-eighties was patented. Since then, the element base has changed quite a lot and it has been possible to simplify the circuit, preserving the idea itself and getting the best characteristics without compromising reliability.

The circuitry of the entire line of these amplifiers is almost the same, they differ only in the number of terminal transistors – in the MOSFIT-100 version, one pair is used, in the MOSFIT-400 variant – 4 pairs.

The circuit has a preliminary buffer voltage amplifier made on the TL071 op amp and a two-stage push-pull power amplifier. The circuitry of the output stage is constructed in such a way that, in fact, it is two independent amplifiers – for the positive half-wave of the sound signal (VT1 – driver, VT3, VT5, VT7, VT9 – terminal transistors) and for the negative half-wave (VT2 – driver, VT4, VT6, VT8, VT10 – terminal transistors). Both amplifiers are covered by their local negative feedbacks: R13-R9 and R14-R10. The gain depends on the ratio of the ratings of these resistors, and in this case it is chosen in such a way as to obtain minimal distortion in this cascade.

Changing the ratings is not recommended (R9 and R10 can be from 27 to 43 Ohms, optimally – 33 or 39 Ohms). Since the last stage operates in the amplifier mode, entering the saturation mode, the resistance between the output of the amplifier and the power source becomes the minimum possible (0.2 – 0.5 Ohm). It is this factor that allows MOSFIT to have a much higher efficiency at the output compared to traditional amplifiers with emitter followers, since the amplitude of the output signal is only a few volts less than the supply voltage.

400W Amplifier Circuit schematic


In addition to local negative feedback (OOS), the entire amplifier is covered by another OOS branch, consisting of R2 and R32. In this case, the gain is KU = R32 / R2 + 1 = 48 times (33 dB). Within small limits, you can change R2 to obtain the required gain, but do not exceed 37 dB (R2 should not be less than 680 Ohms) The list of elements necessary for self-assembly of the amplifier is summarized in the table below.

Terminal transistors are installed on the radiator through electrically insulating heat-conducting gaskets, having previously lubricated the flanges with heat-conducting paste. A “common” wire should be fed to the radiator. However, you can do without gaskets, but it should be borne in mind that the output signal of the amplifier will be present on the radiator, which can cause the excitation of the amplifier, the radiator must be isolated from the case. In fig. 2 shows a drawing of a printed circuit board and the location of parts on it.

Of the features of the amplifier, it should also be noted that the flanges of the terminal transistors are electrically connected between themselves and the output of the amplifier, so when using small heat sinks with forced cooling, you can not use dielectric gaskets, but rather isolate the radiator from the case. When using heat sinks with natural air convection, the dimensions of the latter already become large and it is not recommended to supply an amplifier output to it – too much interference will be created, which, if the boards are installed incorrectly in the case, can cause the amplifier to excite, even despite its rigid stability.

In fig. Figures 3 and 4 show voltage maps for a variant of a 200 W amplifier with a ± 45 V supply voltage and two pairs of terminal transistors and a 400 W amplifier with a ± 65 V supply voltage. Both variants are loaded on the speaker equivalent (yellow rectangle) and do not use ideal power supplies with their own resistance.


Voltage map of a 200 W power amplifier and ± 45V power supply


Voltage map of a 400 W power amplifier and ± 65V power supply


Perhaps it is worth noting that the model used IRF640-IRF9640 transistors, as the closest analogs to the IRFP240-IRFP9240, but with a lower power dissipation by the heat crystal, since they have a TO-220 housing against TO-247. Nevertheless, the IRF640-IRF9640 in the simulator completely coped with the tasks assigned to them, and can also be used in the amplifier as terminal transistors.

However, when using TO-220 cases, one should not forget that the power of one TO-220 case should not exceed 60 W, unlike the TO-247 case, up to 100 … 120 W. In other words, when using an IRF640-IRF9640 as a terminal transistor, it is not recommended to shoot more than 240 watts from an amplifier with four pairs. Figures 5 and 6 show maps of currents flowing through each element of the amplifier in standby mode (no input signal).

Current map of the power amplifier at a supply voltage of ± 45 V


Current map of the power amplifier at a voltage of ± 65V


The quiescent current of the terminal stage should be set within 30-40 mA – this is quite enough for the complete disappearance of distortions of the “step” type and the technological reserve for increasing the supply voltage. This is worth mentioning separately: this amplifier does not have any current-stabilizing chains, therefore, when the supply voltage changes, the operating modes of the terminal stage will also change – with an increase in the supply, the quiescent current will increase, with a decrease, it will decrease.

This does not matter much if the mains voltage varies within 5% or a stabilized power supply is used for the amplifier, but if the mains voltage decreases by 10%, which happens quite often on the periphery, then a step is already guaranteed to appear on the amplifier output, and if increases by 10%, then the quiescent current will already be 0.45 A, and the power allocated to each transistor (when powered ± 65 V + 10% and four pairs of powerful transistors) will be about 30 W, which ultimately will cause heat generation of about 200 W, moreover, on ho Ost go!

For this reason, it is recommended to use the amplifier as a broadband with a high-quality supply voltage, or as an amplifier for a subwoofer and setting the quiescent current within 15 – 20 mA. With a decrease in power supply, the “step” that appears is a low-frequency dynamic head is simply not able to reproduce due to the inertia of the diffuser, and with an increase in the quiescent current it will remain within the permissible and such a strong heating of the heat sink will not occur.

As thermostabilizing elements, VD3-VD4 diodes are used, which can be installed both on the radiator and remain on the printed circuit board – instant heating does not occur anyway, therefore the heating speed of the board installed above the radiator is quite enough. Figure 7 shows the currents flowing in cascades at a temperature of 20 ° C, and in Figure 8 – at a temperature of 60 ° C, that is, with a temperature increase of 3 times.




Published: 2019/08/08 Tags: ,

8 Comments “IRFP240 IRFP9240 Mosfet 400W Amplifier Circuit

  1. projets de circuits electroniques

    IRFP240 IRFP9240 Circuit d’amplification Mosfet 400W

    Malgré l’apparente simplicité, cet amplificateur a montré d’excellents paramètres de qualité, ce qui vous permet de le classer en toute sécurité en tant qu’équipement Hi-Fi. L’amplificateur a un son très agréable au milieu des années 80 a été breveté. Depuis lors, la base de l’élément a beaucoup changé et il a été possible de simplifier le circuit, en préservant l’idée elle-même et en obtenant les meilleures caractéristiques sans compromettre la fiabilité.

    Le circuit de toute la ligne de ces amplificateurs est presque le même, ils ne diffèrent que par le nombre de transistors terminaux – dans la version MOSFIT-100, une paire est utilisée, dans la variante MOSFIT-400 – 4 paires.

  2. sriram

    Salut si je veux utiliser 100W c’est MOSFET-100. Alors quelle est la tension que je dois fournir à ce circuit.

    Puis-je fournir une inductance de 1000nH du côté du haut-parleur de sortie

    1. gevv Contributor


      100W ± 35 V
      200W ± 45 V
      400W ± 65 V

      no need to use inductor on output

  3. Gary singh

    Hi good day to you, I have a monitor box and the amplifier is not working. Could you give me 1000w amplifier layout for it with schematic,I would like to make it at home please give me a simple layout

  4. Tóth Sándor Lőrinc

    Is it possible to operate with a voltage of 92 volts?
    then what will be its performance?

  5. Tóth Sándor Lőrinc

    sorry, I meant to write 2* 92 volt +/-.

  6. gevv Contributor


    2x92v high value not tested max you can use 2x80v.

    generally 2x70v is ideal


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